Question

show that kinetic energy is dimensionally correct​
explain step by step in dimensional formulas​

Answer 1

Explanation:

Derivation

Kinetic energy (K.E) = [Mass × Velocity2] × 2-1 . . . . . (1)

The dimensional formula of Mass = [M1 L0 T0] . . . . (2)

Since, Velocity = Distance × Time-1 = [L] × [T]-1

∴ The dimensional formula of velocity = [M0 L1 T-1] . . . . (3)

On substituting equation (2) and (3) in equation (1) we get,

⇒ Kinetic energy = [Mass × Velocity2] × 2-1

Or, K.E = [M1 L0 T0] × [M0 L1 T-1]2 = [M1 L2 T-2]

Therefore, Kinetic Energy is dimensionally represented as [M1 L2 T-2].

Mark my answer as brainliest mate, ✍️✍️

Answer 2

~$\small \blue {\sf{Answer }}$✨❤

The dimensional formula of Kinetic Energy is given by,

[M1 L2 T-2]

Where,

M = Mass

L = Length

T = Time

Ｄｅｒｉｖａｔｉｏｎ :-

Kinetic energy (K.E) = [Mass × Velocity2] × 2-1 . . . . . (1)

The dimensional formula of Mass = [M1 L0 T0] . . . . (2)

Since, Velocity = Distance × Time-1 = [L] × [T]-1

∴ The dimensional formula of velocity = [M0 L1 T-1] . . . . (3)

On substituting equation (2) and (3) in equation (1) we get,

⇒ Kinetic energy = [Mass × Velocity2] × 2-1

Or, K.E = [M1 L0 T0] × [M0 L1 T-1]2 = [M1 L2 T-2]

Therefore, Kinetic Energy is dimensionally represented as [M1 L2 T-2].

$\huge \orange {\mathfrak{Thank You }}$