Question

Show that kinetic energy of 1mol of an ideal gas is3/7kt

Answer 1

Answer:

A.

2

3

RT

Average kinetic energy of a molecule is KE

avg

=

2

3

KT

KE

total

=

2

3

nN

A

KTn= number of moles.

=

2

3

nRT as N

A

K=R

=

2

3

RT for n=1mole.

Answer 2

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• 3/2RT

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Average kinetic energy of a molecule is KEavg =3/2KT

KEtot = 3/2nNaKT, where n=no.of moles

===> 3/2nRT as NaK = R

===>3/2 RT (for n = 1 mole)(substituting one in place of n)

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