show that length AH >sum of lengths of AB+BC+CD
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AH=AB+BC+CD+DE+EF+FG+GH
SO ah is greatr than AB+BC+CD
SO ah is greatr than AB+BC+CD
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5.3. AB + BC + CD = AD [AB, BC and CD are the parts of AD] Here AD is also the parts of AH. According to Euclid's axioms, the wholes is greater than the part. i.e., AH > AD So, Length AH > sum of the length of AB + BC +CD
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