Question

show that line 5x+6y-1=0 as and 6x-5y+3=0 are perpendicular
​

Answer 1

Answer:

If the lines are perpendicular, that means they intersect at a point and for the lines to intersect, this case should be followed there,

a1/a2 ≠ b1/b2 --- (1)

Given,

a1 = 5

a2 = 6

b1 = 6

b2 = -5

Putting the values in the first eqn...

5/6 ≠ 6/-5

Hence Proved!

hope it helps! :)

Answer 2

Answer:

straight line 5x+3y-1=0,6x+5y=0