Math, asked by ebidumemedi, 2 months ago

show that Lipchitz continues function is of bounded variation

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Answered by santoshgupta9495
0

Functions of bounded variation are precisely those with respect to which one may find Riemann–Stieltjes integrals of all continuous functions. ... Continuously differentiable ⊆ Lipschitz continuous ⊆ absolutely continuous ⊆ continuous and bounded variation ⊆ differentiable almost everywhere.

Answered by ychirag541
0

Answer:

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