Question

show that log (1+2+3) = log 1+ log 2 +log 3​

Answer 1

Answer:

Step-by-step explanation:

To prove, log(1+2+3) = log1+log2+log3

Proof: L.S.H. = log(1+2+3)

= log(6)

= log(1.2.3) [here (.) means the multiply]

= log(1)+log(2)+log(3) [therefore, log(x.y.z)=log(x)+log(y)+log(z)]

= log1 + log2 + log3

= R.H.S.

Hope, it will help you