Show that log (1+2+3)=log1+log2+log3
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we know
log(ab)=loga+logb
log(6)=log(1+2+3)
log(2×3)=log(1+2+3)
log2+log3=log(1+2+3)
log(1×2)+log3=log(1+2+3)
log1+log2+log3=log(1+2+3)
hence
log(1+2+3)=log1+log2+log3
log(ab)=loga+logb
log(6)=log(1+2+3)
log(2×3)=log(1+2+3)
log2+log3=log(1+2+3)
log(1×2)+log3=log(1+2+3)
log1+log2+log3=log(1+2+3)
hence
log(1+2+3)=log1+log2+log3
Bubli1:
No i dont think so it crct
once check it naa plzz
ya this is apply only on contain 1 but all are no contain 1
wat can u explain it briefly
ho
but log1=0 remember it!!!!
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