Question

Show
that log 108/605=2 log2 +3 log3-log5-
2log11​

Answer 1

Answer:

given,  

LHS

=log108/605

=log108-log605

=log(4*27)-(log(5*121))

=log4+log27-log5-log121

=log($2^{2}$)+log($3^{3}$)-log5-log($11^{2}$)

=2log2+3log3-log5-2log11

=RHS

LHS=RHS

Hence proved

Answer 2

Answer:

Step-by-step explanation:

L.H.S = log 108/605

= log 108 - log 605   [∵ log m/n = log m - log n]

= log(2² × 3³) - log (5¹ × 11²)

= [log 2² ₊ log 3³] - [log 5 ₊ log 11²]  [∵ logmn = logm ₊ logn ]

= 2 log 2 ₊ 3 log 3 - log 5 - 2 log 11 = R.H.S  

= hence proved