Show that log 162/343 +2log7/9-log 1/7 =log 2
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Step-by-step explanation:
Log(a×b) = log a + log b
Log(a÷b) = log a - log b
nLog a = log a^n
Using the above properties-:
=log[(162/343)×(49/81)] - log(1/7) ----------------- [2log7/9 = log 49/81]
=log[(2/7)÷(1/7)]
=log2
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