Math, asked by Shefali1267, 1 day ago

show that log 162/343 + 2log7/9 -log1/7=2

Answers

Answered by shifagio13

0

Answer:

log162/343+log(7*7/9*9)-log(1/7)(mlogn=logn^m)

log162/343+log(49/81)(7/1)(logm-logn=log(m/n))

log(162/343)(343/81)(logm+logn=logmn)

log(2/1)=log2=2

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