Question

show that log (243/343) = 5 log 3 - 3 log 7​

Answer 1

hey mate here is ur answer

243=3⁵

343=7³

log(a/b)=log a-log b

log (243/343)=log 243-log 343

=log (3)⁵-log(7)³

=5log3-3log7

hope it helps.

☆☆☆

:-)

Answer 2

Answer:

Step-by-step explanation:

To solve this question we need to know 2 formulae of LOGARITHMS-:

*log(a/b) = log(a) - log(b)

* log(a↑n)= nlog(a) [power comes out of log]

in this question

=>log(243/343) = log(243)-log(343)

=>log(243)= log(3↑5) =5log(3)     [3 raised to the power of 5 is 243]

=>log(343)= log(7↑3) = 3log(7)     [7 raised to the power of 3 is 343]

 

therefor

log(243/343) = 5log(3) - 3log(7)