Show that log 360=3 log2 + 2 log3 + log5
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Step-by-step explanation:
log 360
Prime factorization 360
We write 360= 2^3 ×3^2 ×5
or, log 360
= log (2^3 ×3^2 ×5
Using log (a x b x c) = log a +log b +log c
= log 2^3 +log 3^2 + log 5
Using log a^b = b log a
we write,
= 3 log 2 + 2 log 3 + log 5. (=RHS)
Hence proved.
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