Question

show that; log 50/147=log 2 +log 5-log 3-2 log7

Answer 1

hope it helped and also there should be 2 berfore that log5

Answer 2

SOLUTION -:

Taking the left hand side,

$log( \frac{50}{147} ) \\ = log( \frac{2 \times 25}{3 \times 49} ) = log2 + log25 - log \: 3 - log49$

$= log2 \: + log \: (5 {}^{2} ) \: - \: log \: 3 \: - log(7) {}^{2} \\ \\ = log 2 + 2 \: log5 - log3 - 2log \: 7 \\ this \: is \ right \: hand \: side$