Math, asked by challamallatanvik, 8 months ago

show that (log tan 1°) (log tan 2°)(log tan 3°)..........(log tan 89°)= 0​

Answers

Answered by sathyamargerate0410
0

Step-by-step explanation:

(log tan 1°) (log tan 2°)(log tan 3°)..........(log tan 89°)

log tan1°.....logtan45°.....(logtan89°)

log tan1°.....log1.....(logtan89°)

log tan1°..... (0)..... (log tan89°)

0

Answered by sarivuselvi
0

Answer:

tan(45)=1

Log tan45

=log(1)

=0*0

=0

Similar questions