show that log x base a× log y base b = log x base b× log y base a
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Step-by-step explanation:
L.H.S = log x base a * log y base b
by interchanging of the base formula we get ; [ log m base n = log m / log n
= ( log x / log a ) * ( log y / log b )
= (log x / log b ) * ( log y / log b ) [ just exchanging the base]
so we can write :
= log x base b * log y base a = R.H.S proved.
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