Show that log1000= 3 log2+3log5
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Answer:
The key rule you need to refer to is:
log ab = log a + log b
So
log 1000 = log ( 10 × 10 × 10 )
= log ( 2 × 2 × 2 × 5 × 5 × 5 )
= log 2 + log 2 + log 2 + log 5 + log 5 + log 5
= 3 log 2 + 3 log 5
This can be made a bit shorter if you also use the rule:
log aⁿ = n log a
Then it is just
log 1000
= log ( 2³ × 5³ )
= log 2³ + log 5³
= 3 log 2 + 3 log 5
Hope this helps!
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