Question

Show that log1000=3log2+3log5​

Answer 1

Logarithm laws applied for solving: 1 : log ( a * b) = log a + log b 2: log (a/b) = log a - log b 3 : log a^b = b log a Log 500 = log( 5^3 * 2²) = log 5^3 + log 2² = 3 log5 + 2log2 = 3 log (10/2) + 2 * 0.3010 = 3 * ( log10 - log2 ) + 0.6020 = 3*y

Answer 2

Answer:

mark it

Step-by-step explanation:

it will be your answer