Question

show that log129600=6logpower2+4log3+2log5​

Answer 1

Answer:Lhs = log 10800

= log(2*2*2*2*3*3*3*5*5) [ write 10800 product of prime factors]

= log (2^4)* (3^3)*5^2

= log 2^4 + log 3^3 + log 5^2 [ ∵ log xyz = log x +log y +log z]

= 4log2 + 3 log 3 + 2 log 5 [ ∵ log a^n = n log a ]

= RHS

Step-by-step explanation: