Question

show that log162/343 +2log 7/9 - log 1/7 =log2​

Answer 1

Answer

We Have To Prove

$→ log( \frac{162}{343} ) + 2 log( \frac{7}{9} ) - log( \frac{1}{7} ) = log2$

Left Hand Side,

$→ log( \frac{162}{343} ) + 2 log( \frac{7}{9}){}^{2} - log( \frac{1}{7} )$

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