Question

show that ½ log9 + 2log6 +¼ log81 -log12= 3log3 step by step​

Answer 1

Answer:

$\frac{1}{2} log(9) + 2 log(6) + \frac{1}{4} log(81) - log(12) \\ log( {9}^{ \frac{1}{2} } ) + log( {6}^{2} ) + log( {81}^{ \frac{1}{4} } ) - log(12) \\ (using \: the \: property \: \: n log(m) = log( {m}^{n} ) ) \\ log(3) + log(36) + log(3) - log(12) \\ log(( \frac{3 \times 36 \times 3}{12} ) \\ log(27) \\ log( {3}^{3} ) \\ 3 log(3) \\ log(m) + log(n) = log(m \times n) \\ \: and \: log(m) - log(n) = log( \frac{m}{n} )$

Thanku hope u will understand