Show that logab logbc logca=1
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I think your question
log(a base b).log (b basec).log (d basec)=1
LHS=(logb/loga). (logc/logb).(loga/logc)
=1=RHS
log(a base b).log (b basec).log (d basec)=1
LHS=(logb/loga). (logc/logb).(loga/logc)
=1=RHS
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