Question

→Show that m - 1 is a factor of m^21 - 1 and m^22 - 1​

Answer 1

Solution:

p(m) = m^21 - 1

f(m) = m^22 - 1

g(m) = m - 1

          m - 1 = 0

      ∴ m = 1

Substituting m as 1,

p(1) = (1)^21 - 1

= 1 - 1

=0

Therefore, g(m) is a factor of p(m)

Substituting m as 1 in f(m),

f(1) = (1)^22 - 1

= 1 - 1

=0

Therefore, g(m) is a factor of f(m).

Answer 2

Answer:

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