show that ,m-1 is factor of m11-1 and m12-1
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Let f(m)=m
21
−1 and g(m)=m
22
−1.
The remainders when f(m) and g(m) are divided by m−1 are f(1) and g(1) respectively.
Now f(1)=0=g(1).
Now by factor theorem, as the remainders are zero, so the f(m) and g(m) are perfectly divisible by m−1.
So m−1 is a factor of the given expressions.
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