Question

show that m+6 is a factor of m^2m-42​

Answer 1

Answer:

pur m + 6 = 0

so, m = - 6

Consider p(- 6) =

${( - 6)}^{2} - ( - 6) - 42 \\ = 36 + 6 - 42 \\ = 0$

now, p(- 6) = 0

therefore, m + 6 is a factor of m^2 -m - 42