Question

Show that n^2-n is divisible by 2 for every natural number n.




Plz answer it fast...........

Answer 1

Answer:

n^2-n = n(n-1)

let a be any natural number

Dividing a by 2 we get,

a = 2b + r

r can be 0 or 1

If r = 0, a = 2b, then n is even

If 2 = 1, a = 2b + 1, then n+1 is even

Therefore n^2-n is divisible by 2 for every natural number n.

Step-by-step explanation: