Show that n^2-n is divisible by 2 for every natural number n.
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Answer:
n^2-n = n(n-1)
let a be any natural number
Dividing a by 2 we get,
a = 2b + r
r can be 0 or 1
If r = 0, a = 2b, then n is even
If 2 = 1, a = 2b + 1, then n+1 is even
Therefore n^2-n is divisible by 2 for every natural number n.
Step-by-step explanation:
CaptainAmerica0018:
Thnx bruh
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