Question

Show that n(m square-1)=2m if sin theta +cos theta=m and sec theta +cosec theta=n​

Answer 1

Answer:

this the answer lol............

Answer 2

Answer:

LHS,

n(m²—1) =

$(sec \alpha + cosec \alpha )((sin \alpha + cos \alpha ) {}^{2} - 1) =$

$( \frac{1}{cos \alpha } + \frac{1}{sin \alpha } )( {sin}^{2} \alpha + {cos}^{2} \alpha + 2sin \alpha \: cos \alpha - 1) =$

$\frac{sin \alpha + cos \alpha }{sin \alpha \: cos \alpha } \times (1 + 2sin \alpha \: cos \alpha - 1) =$

$\frac{sin \alpha + cos \alpha }{sin \alpha \: cos \alpha } \times 2sin \alpha \: cos \alpha =$

$2(sin \alpha + cos \alpha ) = 2m$

RHS. Proved.