Question

Show that n(m2-1)=2m, I m= sin theta + cos theta and n= sec theta+ cosec theta​

Answer 1

Answer:

2m (theta=θ)

Step-by-step explanation:

sin theta + cos theta= m, sec theta + cosec theta = n.

Consider LHS

n(m^2 - 1)n(m

2

−1)

(sec\theta + cosec\theta)[(cos\theta + sin\theta)^2 - 1](secθ+cosecθ)[(cosθ+sinθ)

2

−1]

(sec\theta + cosec\theta)[cos^2 \theta + sin^2 \theta + 2sin\theta cos\theta-1]

(secθ+cosecθ)[cos

2

θ+sin

2

θ+2sinθcosθ−1]

sec\theta 2sin\theta cos\theta + cosec\theta . 2sin\theta cos\thetasecθ.2sinθcosθ+cosecθ.2sinθcosθ

2sin\theta + 2 cos\theta2sinθ+2cosθ

2[sin\theta + cos\theta]2[sinθ+cosθ]

= 2m

PLEASE MARK ME AS THE BRAINIEST!!!