show that n square minus 1 is divisible by 8 if n is an odd positive integer
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(n²-1)%8=0
1²=1
3²=9
5²=25
7²=49
9²=81
from above its evident that every square of an odd number is odd
(n+1)(n-1)
let's check with n= 1
2×0=0
divisible by 8
n=3
(3+1)(3-1)=8
divisible by 8
n=5
(6)(4)=8
divisible by 8
it is evident that from here any square of odd number is divisible by 8
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perfect Ãñswēr is in the attachment
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