Show that..... n square + n+1 is not divisible by 5 for any n where n is a natural number
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Your answer is given below =》》》
Any natural number it's "
n = 5k
n = 5k±1
n = 5k±2
where k natural number k
Case n = 5k then
n^2+n+1 = 25k^2+5k+1 = 5k(k+1)+1 then not divisible by 5 (remainder 1)
CAse n = 5k±1 then
n^2+n+1 = 25k^2 ± 10k+1 + 5k±1+1 = 5k(5k±1) +2±1 then not divisible by 5 (remainder 3 or 1)
CAse n = 5k±2
n^2+n+1 = 25k^2 ± 10k+4 + 5k±2+1 = 5k(5k±1+1) ± 2 then not divisible by 5 (remainder 2 or 3)
Then
n^2+n+1 not divisible by 5
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