show that no. 8n can never end with digit 0 for any natural no. n
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8n=(2×2×2)n
8n=(2^3)n
Since it do not have 5 in its factor it will never end with 0 digit....
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8n=(2^3)n
Since it do not have 5 in its factor it will never end with 0 digit....
Hope it helps dear!
Plz.mark as a brainliest.
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