show that oa=ob=oc, if o is in the incentre of the equilateral triangle ABC
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Answer:
OA+OB > AB ……(1)
OB+OC > BC ……(2)
OC+OA > AC ……(3)
Adding (1), (2) and (3), we get
2(OA+OB+OC) > (AB+BC+AC)
Dividing both sides by 2, we get
(OA+OB+OC) > 1/2(AB+BC+AC).
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Step-by-step explanation:
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