Math, asked by amitkkaushikfckaushi, 8 months ago

Show that of the diagonals of a quadrilateral bisect each other at right angles then it is a rhombus.

Answers

Answered by ishaansaripalli
0

Please refer the image attached.

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Answered by CandyCakes
2

Step-by-step explanation:

Take quadrilateral ABCD , AC and BD are diagonals which intersect at O.

In △AOB and △AOD

DO=OB ∣ O is the midpoint

AO=AO ∣ Common side

∠AOB=∠AOD ∣ Right angle

So, △AOB≅△AOD

So, AB=AD

Similarly, AB=BC=CD=AD can be proved which means that ABCD is a rhombus.

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