show that one and only one out of an, and + 4, and + 8, and 12 and n + 16 is divisible by 5, Where n is any positive integer
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Hey mate here's your answer...........
answer is +4 or 4
we have to find a number which it can be added to 16
And then divisible by 5
By taking place of n
n+16
by taking n= 4
4 + 16 = 10
And 10 is divisible by 5
Hope it helps mark as brainliest and thanks for following me................
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