Question

Show that one and only one out of
n, n + 2 or n + 4 is divisible by 3,
where n is any positive integer.​

Answer 1

Answer:

Prove that one and only one out of n, n + 2 and n + 4 is divisible by 3, where n is any positive integer . Euclid's division Lemma any natural number can be written as: . ... ⇒ n + 2 = 3q + 1 + 2 = 3q + 3 = 3(q + 1) is divisible by 3. ⇒ n + 4 = 3q + 1 + 4 = 3q + 5 = 3(q + 1) + 2 is not divisible by 3.

Answer 2

Answer:

finish.....thank you very much