show that one and only one out of n n + 4 and + 8 and kasht 12 and n + 16 is divisible by 5 where n is any positive integer
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show that one and only one out of n n + 4 and + 8 and kasht 12 and n + 16 is divisible by 5 where n is any positive integer
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Step-by-step explanation:
n+12 = 5q+3+12 = 5q+15, is divisible by 5 as the remainder is 0. Therefore, in this case only one out of n, n+4, n+8, n+6, n+12 is divisible by 5 which is n+12. When, n = 5q+4, n is not divisible by 5 as the remainder is 4
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