show that one and only out of n,n+3,n+6,n+9(n€N) is divisible by 4
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let n be any positive integer and b=4.then by euclid's division lemma,x=4q+r.
positive remainders are 0,1,2and 3,since 0<=r<4.then x can be 4q/4q+1/4q+2/4q+3.
1. n=4q,it is divisible by 4
2. n=4q+1, n+3=4q+1+3=4q+4
=4(q+1),it is divisible by 4
3. n=4q+2, n+6=4q+2+6
=4q+8
=4(q+2),it is divisible by 4
4. n=4q+3, n+9=4q+3+9
=4q+12
=4(q+3) ,it is divisible by 4
therefore one and only one out of n,n+1,n+2,n+3 is divisible by 4
i hope its helpful
positive remainders are 0,1,2and 3,since 0<=r<4.then x can be 4q/4q+1/4q+2/4q+3.
1. n=4q,it is divisible by 4
2. n=4q+1, n+3=4q+1+3=4q+4
=4(q+1),it is divisible by 4
3. n=4q+2, n+6=4q+2+6
=4q+8
=4(q+2),it is divisible by 4
4. n=4q+3, n+9=4q+3+9
=4q+12
=4(q+3) ,it is divisible by 4
therefore one and only one out of n,n+1,n+2,n+3 is divisible by 4
i hope its helpful
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