Question

Show that one root of the quadratic equation :- x² + (3-20) x - 60 =0
is -3 hence
find
other root​

Answer 1

Answer:

p(x)=x²+(3-20)x-60=0

x²-17x-60

p(-3)=(-3)²-17(-3)-60

9+51-60

60-60

0

since p(-3)=0

therefore,

-3 is root of the equation

since , -3 is root

therefore , x+3 is a factor

x²-17x-60

x+3

x-20

therefore, other root is 20