Question

show that only one out of n,n+4,n+8,n+12,n+16 is divisible by 5, when n is a positive integer
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Answer 1

Answer:

n + 16 = 5 q + 4 + 16 = 5 q + 20 , which is divisible by 5. Hence, in each case, only one out of n , n + 4 , n + 8 , n + 12 and is divisible by 5.

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Answer 2

Answer:

take n as any natural number.

Example: n=1

:. 1,1+4,1+8, 1+12, 1+16

add all this number

1+1+4+1+8+1+12+1+16

= 2+5+9+13+16

=7+22+16

=29+16

=45.

Here 45 is divisible by 5

that's: 9×5= 45

I think this is the answer. But I am not sure

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