Question

show that p-1 is a factor of p^10-1 and p^11-1​

Answer 1

let p -1 = 0

then p = 1

Now put the value of p

So

p^10-1

where the p value is 1

therefore

1^10-1 = 1

ND

1^11-1 = 1

Answer 2

Answer:

1) f(x) = p10 – 1

g(x)=p-1

g(0)=p=1

f(1) = 1 – 1 = 0

2) p(x) = p11 – 1

g(1) = 1 -1 = 0

hope it helps

Step-by-step explanation: