Question

show that p-1 is a factor of p¹⁰+p⁸+p⁶-p⁴-p²-1​

Answer 1

Ans

yes it is a factor

Step-by-step explanation:

by substituing in 1 eqn we get sum as 0 so p-1 is a factor of given eqn

Answer 2

Answer:

p-1=0

p=1

putting p=1

=P^10+P^8+P^6-P^4-P^2-1

=1^10+1^8+1^6-1^4-1^2-1

=1+1+1-1-1-1

=3-3

hence,

=(P-1) is a factor of P^10+P^8+P^6-P^4-P^2-1