show that p-1 is a factor of p10-1 and also of p11-1.
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First of all (p - 1) is not the factor of p10.
F(x) = p10 – 1
F(1) = 1 – 1 = 0
G(x) = p11 – 1
G(1) = 1 -1 = 0
DibyaPrakashnayak:
Nice
Answered by
6
Answer:
1) f(x) = p10 – 1
g(x)=p-1
g(0)=p=1
f(1) = 1 – 1 = 0
2) p(x) = p11 – 1
g(1) = 1 -1 = 0
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