Question

show that p-1 is a factor of p10-1 and also of p11-1.

Answer 1

First of all (p - 1) is not the factor of p10.
F(x) = p10 – 1
F(1) = 1 – 1 = 0
G(x) = p11 – 1
G(1) = 1 -1 = 0

Answer 2

Answer:

1) f(x) = p10 – 1

g(x)=p-1

g(0)=p=1

f(1) = 1 – 1 = 0

2) p(x) = p11 – 1

g(1) = 1 -1 = 0

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