Show that p-1 is a factor of p10-1 and also p11 -1
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Answered by
1
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1) f(x) = p10 – 1
g(x)=p-1
g(0)=p=1
f(1) = 1 – 1 = 0
2) p(x) = p11 – 1
g(1) = 1 -1 = 0
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