Question

show that p-1 is a factor of p11-1​

Answer 1

Answer:

Step-by-step explanation:

let p be 11

11-1=10

11*11=121

121-1=120

as 10 is a factor of 120, it is proved that p-1 is factor 11p-1

Answer 2

Step-by-step explanation:

for p-1 to be a factor of $g(p)=p^1^1-1$,

By factor Theorem

$g(1)$ should be zero

$g(1)=(1)^{11}-1=1-1=0$

Now since g(1)=0

Therefore, p-1 is a factor of g(p)

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