show that ( p-1 ) is a factor (p¹⁰ -1 ) and also p¹¹ - 1
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Answered by
1
Step-by-step explanation:
p-1=0
=>p=1
=>(1)^10-1
=>1-1=0
hence (p-1) is a factor of (p^10-1)
also it is the factor of (p^11-1)
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