Question

show that p-1 is the factor of both p^10-1 and p^11-1..​

Answer 1

Answer:

Factor

Step-by-step explanation:

p - 1 is a factor so,

p - 1 = 0

p = 1

now, P(p) = $p^{10} - 1$

                  = $1^{10} - 1$

                  = 1 - 1

                  = 0

hence p-1 is a factor of $p^{10} - 1$.

similarly p-1 is also a factor of $p^{11} - 1$.