Math, asked by mauryaansh8, 4 months ago

show that p-1 is the factors of p^3-1 .step by step

Answers

Answered by apati2206

0

Answer:

Proved below

Step-by-step explanation:

P^3-1 = (P-1)(p^2+p+1) as a^3-b^3=(a-b)(a^2+ab+b^2)

So, p-1 is a factor

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