show that p=3i+j-3k, q=4i-6j-2k and r=i-7j+k can form the sides of triangle. Calculate the area of triangle
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p=3i+j-3k
q=4i-6j-2k
r=i-7j+k
Then sum of
3i+j-3k+4i-6j-2k+i-7j+k
8i-12j-4k
Then area
==>
== (8i-12j-4k) /2
===>.
4i-6j-2k
Hope it's helpful
p=3i+j-3k
q=4i-6j-2k
r=i-7j+k
Then sum of
3i+j-3k+4i-6j-2k+i-7j+k
8i-12j-4k
Then area
==>
== (8i-12j-4k) /2
===>.
4i-6j-2k
Hope it's helpful
bushraamyousuf:
this is not area this is perimeter of triangle. Area is base *height /2
Hey miss! Last me area hi Maine Likha hai plzz see carefully..okay na
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