Question

Show that P-7,P-10,P-13,P-16,P-19 are in AP. Find it's 8th term and common difference​

Answer 1

Answer:

what you mean bro

Step-by-step explanation:

Answer 2

p-7 as the 1st Term (T1) ,

p-10 as the 2nd Term (T2) ,

p-13 as the 3rd Term (T3) ,

p-16 as the 4th Term (T4) , and

p-19 as the 5th Term (T5) .

A is the variable which demonstrates the 1st Term (T1) . and ,

D is variable that gives us the uniform difference between two terms .

So ,

D = T2 - T1

Therefore , D = ( p-7 )-( p-10 )

D = - 3 .

D = T3 - T2

Therefore , D = ( p-13 )-( p-10 )

D = - 3 .

D = T4 - T3

Therefore , D = ( p-16 )-( p-13 )

D = - 3 .

D = T5 - T4

Therefore , D = ( p-19 )-( p-16 )

D = - 3 .

In each case , The value of D is uniform .

So , we can say that the terms are in uniform intervals , so they are in AP.

Term 8 (T8) = A + ( 7 * D )

Term 8 (T8) = p -7 + ( 7 * - 3 )

Term 8 (T8) = p -7 - 21

Term 8 (T8) = p - 28 .