Question

show that (p-q)³ +(q-r)³+(r-p)³=3(P-q)(q-r)(r-p)​

Answer 1

Step-by-step explanation:

(p-q)^3+(q-r)^3+(r-p)^3=3(p-q)(q-r)(r-p)

we know, if a+b+c=0

then, a^3+b^3+c^3=3abc

so, p-q+q-r+r-p=0

therefore, (p-q)^3+(q-r)^3+(r-p)^3=3(p-q)(q-r)(r-p)