Question

show that: p(q-r)+q(r-p)+r(p-q)=0.​

Answer 1

Step-by-step explanation:

pq-pr + qr - pq + pr - qr

=pq-pq + pr - pr + qr - qr

=0

Answer 2

Step-by-step explanation:

p(q-r)+q(r-p)+r(p-q)=0

pq-pr+qr-pq+rp-qr=0

pq-pq-pr+pr+qr-pr=0

0=0 proved